0=36+37x+7x^2

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Solution for 0=36+37x+7x^2 equation:



0=36+37x+7x^2
We move all terms to the left:
0-(36+37x+7x^2)=0
We add all the numbers together, and all the variables
-(36+37x+7x^2)=0
We get rid of parentheses
-7x^2-37x-36=0
a = -7; b = -37; c = -36;
Δ = b2-4ac
Δ = -372-4·(-7)·(-36)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-19}{2*-7}=\frac{18}{-14} =-1+2/7 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+19}{2*-7}=\frac{56}{-14} =-4 $

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